In this paper we consider the problem of finding the n-sided (\documentclass[12pt]{minimal}
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$n\geq 3$\end{document}) polygons of diameter 1 which have the largest possible width wn. We prove that \documentclass[12pt]{minimal}
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$w_4=w_3= {\sqrt 3 \over 2}$\end{document} and, in general, \documentclass[12pt]{minimal}
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$w_n \leq \cos {\pi \over 2n}$ \end{document}. Equality holds if n has an odd divisor greater than 1 and in this case a polygon \documentclass[12pt]{minimal}
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$\cal P$\end{document} is extremal if and only if it has equal sides and it is inscribed in a Reuleaux polygon of constant width 1, such that the vertices of the Reuleaux polygon are also vertices of \documentclass[12pt]{minimal}
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$\cal P$\end{document}.