We describe an algorithm for solving an important geometric problem arising in computer-aided manufacturing. When cutting away a region from a solid piece of material—such as steel, wood, ceramics, or plastic—using a rough tool in a milling machine, sharp convex corners of the region cannot be done properly, but have to be left for finer tools that are more expensive to use. We want to determine a toolpath that maximizes the use of the rough tool. In order to formulate the problem in mathematical terms, we introduce the notion of bounded convex curvature. A region of points in the plane Q\documentclass[12pt]{minimal}
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\begin{document}$$Q$$\end{document} has bounded convex curvature if for any point x∈∂Q\documentclass[12pt]{minimal}
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\begin{document}$$x\in \partial Q$$\end{document}, there is a unit disk U and ε>0\documentclass[12pt]{minimal}
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\begin{document}$$\varepsilon >0$$\end{document} such that x∈∂U\documentclass[12pt]{minimal}
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\begin{document}$$x\in \partial U$$\end{document} and all points in U within distance ε\documentclass[12pt]{minimal}
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\begin{document}$$\varepsilon $$\end{document} from x are in Q\documentclass[12pt]{minimal}
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\begin{document}$$Q$$\end{document}. This translates to saying that as we traverse the boundary ∂Q\documentclass[12pt]{minimal}
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\begin{document}$$\partial Q$$\end{document} with the interior of Q\documentclass[12pt]{minimal}
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\begin{document}$$Q$$\end{document} on the left side, then ∂Q\documentclass[12pt]{minimal}
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\begin{document}$$\partial Q$$\end{document} turns to the left with curvature at most 1. There is no bound on the curvature where ∂Q\documentclass[12pt]{minimal}
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\begin{document}$$\partial Q$$\end{document} turns to the right. Given a region of points P\documentclass[12pt]{minimal}
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\begin{document}$$P$$\end{document} in the plane, we are now interested in computing the maximum subset Q⊆P\documentclass[12pt]{minimal}
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\begin{document}$$Q\subseteq P$$\end{document} of bounded convex curvature. The difference in the requirement to left- and right-curvature is a natural consequence of different conditions when machining convex and concave areas of Q\documentclass[12pt]{minimal}
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\begin{document}$$Q$$\end{document}. We devise an algorithm to compute the unique maximum such set Q\documentclass[12pt]{minimal}
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\begin{document}$$Q$$\end{document}, when the boundary of P\documentclass[12pt]{minimal}
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\begin{document}$$P$$\end{document} consists of n line segments and circular arcs of arbitrary radii. In the general case where P\documentclass[12pt]{minimal}
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\begin{document}$$P$$\end{document} may have holes, the algorithm runs in time O(n2)\documentclass[12pt]{minimal}
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\begin{document}$$O(n^2)$$\end{document} and uses O(n) space. If P\documentclass[12pt]{minimal}
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\begin{document}$$P$$\end{document} is simply-connected, we describe a faster O(nlogn)\documentclass[12pt]{minimal}
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\begin{document}$$O(n\log n)$$\end{document} time algorithm.
