Synthesis and crystal structure of trans-bis(O, O′-diisopropylthiophosphoryl-1H-imidazole-N3) bis(O,O′-diisopropyldithiophosphato) nickel(II) complex: Ni[N3-ImSP(OiPr)2]2[S2P(OiPr)2]2 (Im = imidazole; iPr = isopropyl)

The mononuclear complex, Ni[N3-ImSP(OiPr)2]2[S2P(OiPr)2]2 (Im = imidazole; iPr = isopropyl), was unexpectedly obtained in a reaction of bis(O,O′-diisopropyl-dithiophosphato) nickel(II) complex with imidazole ligand, and its structure was determined by X-ray crystallography. It crystallizes in the triclinic system, space group P\documentclass[12pt]{minimal} \usepackage{amsmath} \usepackage{wasysym} \usepackage{amsfonts} \usepackage{amssymb} \usepackage{amsbsy} \usepackage{mathrsfs} \usepackage{upgreek} \setlength{\oddsidemargin}{-69pt} \begin{document} $$\overline {\text{1}} $$ \end{document}, with lattice parameters a = 12.437(3) Å, b = 13.181(3) Å, c = 8.4580(17) Å, α = 93.16(3)°, β = 101.93(3)°, β = 65.26(3)°, and Z = 1. The Ni atom has almost perfect octahedral coordination geometry and is coordinated by two N atoms of imidazole from two O,O′-diisopropylthiophosphoryl-1H-imidazole ligands in axial positions and four S atoms from two (O,O′-diisopropyldithiophosphato) anions which act as bidentate ligands forming a four-membered chelate ring in the equatorial plane. The Ni—S bond distances are 2.469(1) and 2.507(1) Å, and the Ni—N bond distances are 2.097(2) Å. The IR spectra data are in agreement with the structural data.