Bartle-Dunford-Schwartz integration

被引:4
|
作者
Drewnowski, Lech [1 ]
Labuda, Iwo [2 ]
机构
[1] Adam Mickiewicz Univ, Fac Math & Comp Sci, PL-61614 Poznan, Poland
[2] Univ Mississippi, Dept Math, University, MS 38677 USA
关键词
Topological vector space or lattice; Convexly bounded vector measure; Bartle-Dunford-Schwartz integration; Spaces of integrable functions; Dominated Convergence Theorem; Bounded multiplier property; sigma-Lebesgue property; sigma-Levi property; VECTOR MEASURES; OPERATORS; THEOREM; SPACES; BOUNDEDNESS; VALUES; L0;
D O I
10.1016/j.jmaa.2012.12.014
中图分类号
O29 [应用数学];
学科分类号
070104 ;
摘要
We study the BDS-integral, using the original definition, but with respect to a convexly bounded measure mu with values in an arbitrary sequentially complete tvs X. Denote by L-0(mu) the space of mu-measurable R-valued functions. Then all bounded measurable functions are mu-integrable (in an elementary sense), and the space L-1(mu) of BDS-integrable functions is a vector lattice and a topological vector space in its natural topology. We next distinguish the space L-o(1)(mu) as the largest vector subspace of L-1(mu) that is solid in L-0(mu). We prove general convergence theorems for both L-1(mu) and L-o(1)(mu). In particular, we show that (4) with its natural topology is a Dedekind sigma-complete topological vector lattice with the sigma-Lebesgue property, and that the Dominated Convergence Theorem holds in L-o(1)(mu). If X contains no isomorphic copy of c(0), then L-o(1)(mu) has the sigma-Levi property (that is, the Beppo Levi Theorem holds). We identify L-o(1)(mu) as the domain for the Thomas-Turpin integral, and thus show that this integral is simply the restriction of the BDS-integral to L-o(1)(mu). The last two statements answer the questions posed, respectively, by Thomas and Turpin, and left open since the seventies. (C) 2012 Elsevier Inc. All rights reserved.
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页码:620 / 640
页数:21
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